4a^2=28+6a

Solution for 4a^2=28+6a equation:

4a^2=28+6a

We move all terms to the left:

4a^2-(28+6a)=0

We add all the numbers together, and all the variables

4a^2-(6a+28)=0

We get rid of parentheses

4a^2-6a-28=0

a = 4; b = -6; c = -28;
Δ = b2-4ac
Δ = -62-4·4·(-28)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*4}=\frac{-16}{8}
=-2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*4}=\frac{28}{8}
=3+1/2
$